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- TCS PAPER - 24 MAY 2008
TCS PAPER - 24 MAY 2008
- By Chetana S
- Published 21/08/2008
- PREPARATION MATERIALS , 2008 PAPERS
-
Rating:
Chetana S
This is Chetana, owner of the World's Biggest Job Group "CHETANA-JOBS".
View all articles by Chetana STCS Recruitment Rounds
Ø Written Test
Ø Technical Interview
Ø MR (Managerial)
Ø HR Interview
WRITTEN
TEST : (ONLINE TEST)
Contains
3 sections
1) Verbal (Synonyms –
Antonyms - Comprehension Passages)
2) Quantitative
Aptitude
3) Critical Reasoning
SECTION: 1 (Verbal- 30 questions - 20 min)
Ø Synonyms (Refer In
GRE BARRONS 12th Edition )
Ø Antonyms (Refer In GRE BARRONS 12th
Edition (page no -126))
Ø Passage completion
Some of the
previous questions in quant: Go through these models and try to solve them.
They will give same models but they change the data.
SECTION:
2 (QUANT- 38 questions - 40 min)
1) If log 0.317=0.3332 and log 0.318=0.3364 then find log 0.319 =
Sol: Given log 0.317=0.3332 and log 0.318=0.3364
Then
Log
0.319=log0.318+ (log0.318-log0.317)
=0.3396
2) A box of 150 packets consists of 1kg packets and 2kg packets. Total
weight of box is 264kg. How many 2kg packets are there?
Sol: Given x= 2 kg Packs
y= 1 kg packs
=> x + y = 150 .......... Eqn 1
=> 2x + y = 264 .......... Eqn 2
On solving these two equations
x = 114
By using equation 1
114 + y = 150
=> y = 36
=>Number
of 2 kg Packs = 114.
3) My flight takes of at
a) 6:00 am b) 6:40am c)
Sol: (Hint:
Every 1 deg longitude is equal to 4 minutes. If west to east add time else
subtract time)
Ans:
4) A
Flight takes off at
Ans:
5) A moves 3 kms east from his
starting point. He then travels 5 kms north. From that point he moves 8 kms to
the east. How far is A from his starting point?
Ans: 13 kms
6) Aeroplane is flying at a
particular angle and latitude, after some time latitude is given. (8 hrs
later), u r asked to find the local time of the place.
7) An Aeroplane starts from A (SOME
LATITUDE IS GIVEN ACCORDING TO PLACE).At
8) A plane moves from 9°N40°E to
9°N40°W. If the plane starts at
Sol: Since it is moving from east to west longitude we need to
add both
Ie, 40+40=80
Multiply the
ans by 4
=>80*4=320min
Convert this
min to hours i.e., 5hrs 33min
It takes 8hrs totally. So
8-5hr 30 min=2hr 30min
So the ans is
Ans:
9) The size of the bucket is N kb.
The bucket fills at the rate of 0.1 kb per millisecond. A programmer sends a
program to receiver. There it waits for 10 milliseconds. And response will be
back to programmer in 20 milliseconds. How much time the program takes to get a
response back to the programmer, after it is sent?
Sol:
The time being
taken to fill the bucket.
After reaching program it waits there for 10ms and back to the programmer in
20 ms.
then total time to get the response is
20ms +10 ms=30ms
Ans:
30ms
10) A file is transferred from one location to another in ‘buckets’. The
size of the bucket is 10 kilobytes. Eh bucket gets filled at the rate of 0.0001
kilobytes per millisecond. The transmission time from sender to receiver is 10
milliseconds per bucket. After the receipt of the bucket the receiver sends an
acknowledgement that reaches sender in 100 milliseconds. Assuming no error
during transmission, write a formula to calculate the time taken in
seconds to successfully complete the transfer of a file of size N kilobytes.
Ans: (n/1000)*(n/10)*10+ (n/100).... (Not 100% sure)
11)A fisherman's day is rated as good if he catches 9 fishes ,fair if 7
fishes and bad if 5 fishes. He catches 53 fishes in a week n had all good, fair
n bad days in the week. So how many good, fair n bad days did the fisher man
had in the week.
Sol:
good days means --- 9 fishes so 53/9=4 (remainder=17)
if u assume 5 then there is no chance for bad days.
fair days means ----- 7 fishes so remaining 17 ---
17/7=1(remainder=10) if u assume 2 then there is no chance for bad days.
bad days means -------5 fishes so remaining
10---10/5=2days.
4*9=36
7*1=7
2*5=10
36+7+10=53...
Ans:
4 good, 1 fair, 2bad. ==== total 7 days.
12) x+y+z=7--------- eq1
9*x+7*y+5*z=53 -------eq2
Sol:
Multiply
eq 1 by 9,
9*x+9*y+9*z=35
-------------eq3
From
eq2 and eq3
2*y+4*z=10-----eq4
Since
all x, y and z are integer i should put a integer value of y such that z sud be
integer in eq 4.....And there will be two value y=1 or 3 then z = 2 or 1 from
eq 4
For
first y=1,z=2 then from eq1 x= 4
So
9*4+1*7+2*5=53.... Satisfied
Now
for second y=3 z=1 then from eq1 x=3
So
9*3+3*7+1*5=53 ......satisfied
So
finally there are two solution of this question
Ans:
(x,y,z)=(4,1,2) and (3,3,1)...
13) Y catches 5 times more fishes than X. If total number of fishes
caught by X and Y is 42, then number of fishes caught by X?
Sol: let no. of fish x catches=p
No. caught by y =r
r=5p.
Given r+p=42
Then p=7, r=35
14) Three companies are working independently and receiving the savings
20%, 30%, 40%. If the companies work combine, what will be their net savings?
Sol: Suppose total income
is 100
So
amount x is getting is 80
y is 70
z =60
Total=210
But
total money is 300
300-210=90
So
they are getting 90 rs less
90 is
30% of 300 so they r getting 30% discount
15) The ratio of incomes of C and D is 3:4.the ratio of their
expenditures is 4:5.Find the ratio of their savings if the savings of C is one
fourths of his income?
Sol: incomes: 3:4
Expenditures:
4:5
3x-4y=1/4(3x)
12x-16y=3x
9x=16y
y=9x/16
(3x-4(9x/16))/
((4x-5(9x/16)))
Ans: 12/19
16)If A can copy 50 pages in 10 hours and A and B together can copy 70
pages in 10 hours, how much time does B takes to copy 26 pages?
Sol: A can copy 50 pages in 10 hrs.
=>A can copy 5 pages in 1hr. (50/10)
Now A & B can copy 70 pages in 10hrs.
Thus, B can copy 90 pages in 10 hrs. [Eqn. is (50+x)/2=70,
where x--> no. of pages B can copy in 10 hrs.]
So, B can copy 9 pages in 1hr.
Therefore, to copy 26 pages B will need almost 3hrs.
Since in 3hrs B can copy 27 pages
17) A can copy 50 papers in 10 hours while both A & B can copy 70
papers in 10 hours. Then for how many hours required for B to copy 26 papers?
ANS: 13
18) A is twice efficient than B. A
and B can both work together to complete a work in 7 days. Then find in how
many days A alone can complete the work?
ANS: 10.5 (11)
19) A finish the work in 10 days. B
is 60% efficient than A. So how many days does B take to finish the work?
Ans:
100/6 (4 days)
20) A finishes the
work in 10 days & B in 8 days individually. If A works for only 6 days then
how many days should B work to complete A's work?
Ans: 3.2 days (4 days)
21) A man, a woman, and a child can do a
piece of work in 6 days. Man only can do it in 24 days. Woman can do it in 16
days and in how many days child can do the same work?
Ans: 16
22) If 20 men take 15 days to
complete a job, in how many days can 25 men finish that work?
Ans. 12 days
23) One fast typist type some matter in 2hr and another slow typist type
the same matter in 3hr. if both do combine in how much time they will finish.
Ans:
1hr 12min
24) A man shapes 3 cardboards in 50 minutes, how many types of cardboard
does he shape in 5 hours?
Ans: 18cardboards
25) A work is done by two people in 24
min. one of them can do this work a lonely in 40 min. how much time required to
do the same work for the second person.
Sol: (A+B) can do the work in = 1/24 min.
A alone can do the same work in = 1/40
min.
B alone can do the same work in = (A+B)’s
– A’s = 1/24 – 1/40 = 1/60
=> B can do the same work in = 60 min
Ans: 60 min
26) A can do a piece of work in 20
days, which B can do in 12 days. In 9 days B does ¾ of the work. How many days
will A take to finish the remaining work?
27) Anand finishes a work in 7 days;
Bittu finishes the same job in 8 days and Chandu in 6 days. They take turns to
finish the work. Anand on the first day, Bittu on the second and Chandu on the
third day and then Anand again and so on. On which day will the work get over?
A) 3rd b) 6th c) 9th d) 7th
28) 3 men finish painting a wall in 8
days. Four boys do the same job in 7 days. In how many days will 2 men and 2
boys working together paint two such walls of the same size?
A) 6 6/13 days
B) 3 3/13 days
C) 9 2/5 days
D) 12 12/13 days
29) what's the answer for that?
A, B and C are 8 bit no's. They are as follows:
A -> 1 1 0 0 0 1 0 1
B -> 0 0 1 1 0 0 1 1
C -> 0 0 1 1 1 0 1 0 (- =minus, u=union)
Find ((A - C) u B) =?
Sol: We have to find (A-C) U B
To
find A-C, We will find 2's compliment of C and them add it with A,
That
will give us (A-C)
2's
compliment of C=1's compliment of C+1
=11000101+1=11000110
A-C=11000101+11000110
=10001001
Now
(A-C) U B is .OR. Logic operation on (A-C) and B
10001001
.OR. 00110011
The
answer is = 10111011,
Whose
decimal equivalent is 187.
30) A = 10010001
B = 01101010
C = 10010110
(AuB)nC =? [(A union B) intersection C =?]
31) A
=0 0 0 0 1 1 1 1
B =0 0 1 1 0 0 1 1
C =0 1 0 1 0 1 0 1
( A U B ) n C Find the fourth row, having the bit pattern as an integer in an
8-bit computer, and express the answer in its decimal value.
Ans: 29
32) A, B and C are 8 bit nos. They are as follows:
A 1 1 0 1 1 0 1 1
B 0 1 1 1 1 0 1 0
C 0 1 1 0 1 1 0 1
Find ( (A-B) u C )=?
Hint: 109 A-B is {A} - {A n B}
Ans: 0 1 1 1 1 1 1 1 (DB)
33) If A, B and C are the mechanisms
used separately to reduce the wastage of fuel by 30%, 20% and 10%. What will be
the fuel economy if they were used combined.
Ans: 20%
34) In the class of 40 students, 30
speak Hindi and 20 speak English. What is the lowest possible number of
students who speak both the languages?
(a) 5 (b) 20 (c) 15 (d) 10 (e) 30
35) In a two-dimensional array, X (9, 7), with each element occupying 4
bytes of memory, with the address of the first element X (1,
1) is 3000, find the address of
X (8,
5).
Sol: [HINT~ Formula=Base Add + Byte reqd
{N (i-1) + (j-1)}
Where,
Base Add=3000;
Byte reqd=4;
N=no of columns in array=7;
i=8; j=5;
IN ROW MAJOR ORDER]
Ans: 3212
36) If the vertex (5, 7) is placed in
the memory. First vertex (1, 1)’s address is 1245 and then address of (5, 7) is
----------
Ans: 1279
37) A 2D array is declared as A [9,
7] and each element requires 2 byte. If A [1, 1] is stored in 3000. Find the
memory of A [8, 5]?
Ans: 3106
38) One circular array is given
(means the memory allocation takes place like a circular fashion) dimension
(9X7). starting address is 3000.find the address of (2, 3)
Ans: 555
39) The size of a program is N. And the
memory occupied by the program is given by M = square root of 100N. If the size
of the program is increased by 1% then how much memory now occupied?
Sol: N is increased by 1%
Therefore new value
of N=N + (N/100)
=101N/100
M=sqrt (100 *
(101N/100))
Hence, we get
M=sqrt (101
* N)
Ans: 0. 5 %( =SQRT 101N)
40) A bus started from bus stand at 8.00a m and after 30 min staying at
destination, it returned back to the bus stand. The destination is 27 miles
from the bus stand. The speed of the bus 50 percent fast speed. At what time it
retur4ns to the bus stand.
Sol: (this is the step by step solution
:)
A bus
cover 27 mile with 18 mph in =27/18= 1 hour 30 min.
And
it wait at stand =30 min.
After
this speed of return increase by 50% so 50%of 18 mph=9mph
Total
speed of returning=18+9=27
Then
in return it take 27/27=1 hour
Then
total time in journey=1+1:30+00:30 =3 hour
So it
will come at 8+3 hour=11 a.m.
So
Ans==
41) A Flight takes off at
Ans:
42) My flight takes of at
a) 6:00 am b) 6:40am c)
(Hint:
Every 1 deg longitude is equal to 4 minutes. If west to east add time else
subtract time)
Ans:
43) A moves 3 kms east from his
starting point. He then travels 5 kms north. From that point he moves 8 kms to
the east. How far is A from his starting point?
Ans: 13 kms
44) A plane moves from 9°N40°E to
9°N40°W. If the plane starts at