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- TCS PAPER - 24 MAY 2008
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- TCS
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- TCS PAPER - 24 MAY 2008
TCS PAPER - 24 MAY 2008
- By Chetana S
- Published 21/08/2008
- PREPARATION MATERIALS , 2008 PAPERS
-
Rating:
45) In
Ans: at 9 pm 7.5 more or 385.8 (DB)
46) For Temperature a function is
given according to time: ((t**2)/6) + 4t +12 what is the temperature rise or
fall between 4.AM TO 9 AM
Sol:
In equation first put t=9,
We will get 34.5..... (1)
Now put t=4,
We will get 27........ (2)
So Ans=34.5-27
=7.5
47) For Temperature a function is given according to time: ((t**2)/6) + 4t
+12 what is the temperature rise or fall between 5 PM to 8 PM
48) Low temperature at the night
in a city is 1/3 more than 1/2 high as higher temperature in a day. Sum of the
low tem. And highest temp is 100 degrees. Then what is the low temp?
Sol:
Let highest temp be x
So low temp=1/3 of x of 1/2 of x plus x/2 i.e.
x/6+x/2
Total temp=x+x/6+x/2=100
Therefore, x=60
Lowest temp is 40
Ans: (40 deg.)
49) A
person had to multiply two numbers. Instead of multiplying by 35, he multiplied
by 53and the product went up by 540. What was the raised product?
a) 780 b) 1040
c) 1590 d)
1720
Sol: x*53-x*35=540=> x=30 therefore, 53*30=1590
Ans: 1590
50) How
many positive integer solutions does the equation 2x+3y = 100 have?
a) 50 b) 33 c) 16 d) 35
Sol: Given
2x+3y=100, take l.c.m of 'x' coeff and 'y' coeff i.e. l.c.m of 2,3 ==6then
divide 100 with 6, which turns out 16 hence answer is 16short cut formula---
constant / (l.cm of x coeff and y coeff)
51) The
total expense of a boarding house is partly fixed and partly variable with the
number of boarders. The charge is Rs.70 per head when there are 25 boarders and
Rs.60 when there are 50 boarders. Find the charge per head when there are 100
boarders.
a) 65 b) 55 c) 50
d) 45
Sol: let a
= fixed cost and
k = variable cost and n = number of boarders
Total cost when 25 boarders c = 25*70 = 1750 i.e.
1750 = a + 25k
Total cost when 50 boarders c = 50*60 = 3000 i.e.
3000 = a + 50k
Solving above 2 eqns, 3000-1750 = 25k i.e. 1250 =
25k i.e. k = 50
Therefore, substituting this value of k in either
of above 2 eqns we get
a = 500 (a = 3000-50*50 = 500 or a = 1750 - 25*50 =
500)
So total cost when 100 boarders = c = a + 100k =
500 + 100*50 = 5500
So cost per head = 5500/100 = 55
52) Amal
bought 5 pens, 7 pencils and 4 erasers. Rajan bought 6 pens, 8 erasers and 14
pencils for an amount which was half more than what Amal had paid. What % of
the total amount paid by Amal was paid for pens?
a) 37.5% b) 62.5% c) 50%
d) None of these
Sol: Let, 5
pens + 7 pencils + 4 erasers = x rupees
So 10 pens + 14 pencils + 8 erasers = 2*x
rupees
Also mentioned, 6 pens + 14 pencils + 8 erasers =
1.5*x rupees
So (10-6) = 4 pens = (2-1.5) x rupees
So 4 pens = 0.5x rupees => 8 pens = x rupees
So 5 pens = 5x/8 rupees = 5/8 of total (note x
rupees is total amt paid by
Amal) i.e. 5/8 = 500/8% = 62.5%
Ans: 62.5%
53) I lost
Rs.68 in two races. My second race loss is Rs.6 more than the first race. My
friend lost Rs.4 more than me in the second race. What is the amount lost by my
friend in the second race?
Sol: x + x+6
= rs 68
2x + 6 = 68
2x = 68-6
2x = 62
x=31
x is the amt lost in I race
x+ 6 = 31+6=37 is lost in second race
Then my friend lost 37 + 4 = 41 Rs
Ans: 41 Rs
54) A face
of the clock is divided into three parts. First part hours total is equal to
the sum of the second and third part. What is the total of hours in the bigger
part?
Sol:
The clock normally has 12 hr
Three parts x, y, z
x+y+z=12
x=y+z
2x=12
x=6
So the largest part is 6 hrs
Ans:
6 hrs
55) (1-1/6)
(1-1/7).... (1- (1/ (n+4))) (1-(1/ (n+5))) = ?
Sol: Leaving the first numerator and last denominator, all the numerator
and denominator will cancelled out one another. Ans: 5/ (n+5)
56) Ten
boxes are there. Each ball weighs 100 gms. One ball is weighing 90 gms.
i) If there are 3 balls
(n=3) in each box, how many times will it take to find 90 gms ball? ii) Same
question with n=10
iii) Same question with n=9
Sol: The
chances are
When n=3
(i) nC1= 3C1 =3 for 10 boxes.. 10*3=30
(ii) nC1=10C1=10 for 10 boxes ....10*10=100
(iii) nC1=9C1=9 for 10 boxes.....10*9=90
57) With
4/5 full tank vehicle travels 12 miles, with 1/3 full tank how much distance
travels?
Sol:
4/5 full tank= 12 mile
1 full tank= 12/ (4/5)
1/3 full tank= 12/ (4/5)*(1/3) = 5 miles
Ans: 5 miles
58) Wind
flows 160 miles in 330min.for 80 miles how much time required
160 miles?
Sol: 1
mile = 330/160
80 miles= (330*80)/160=165 min.
Ans: 165 min.
59) A
person was fined for exceeding the speed limit by 10mph.another person was also
fined for exceeding the same speed limit by twice the same if the second person
was traveling at a speed of 35 mph. find the speed limit
Sol: ( x+10)
=(x+35)/2
Solving the eqn we get x=15
Ans: 15
60) A sales
person multiplied a number and get the answer is 3 instead of that number
divided by 3.what is the answer he actually has to get.
Sol: Assume
1
1* 3 = 3
1*1/3=1/3
So he has to got 1/3
Ans: 1/3
61) The
size of the bucket is N kb. The bucket fills at the rate of 0.1 kb per
millisecond. A programmer sends a program to receiver. There it waits for 10
milliseconds. And response will be back to programmer in 20 milliseconds. How
much time the program takes to get a response back to the programmer, after it
is sent? Ans: 30 milliseconds
62) A
person who decided to go weekend trip should not exceed 8 hours driving in a
day average speed of forward journey is 40 mph due to traffic in Sundays the
return journey average speed is 30 mph. How far he can select a picnic spot.
63) Car is
filled with four and half gallons of oil for full round trip. Fuel is taken 1/4
gallons more in going than coming. What is the fuel consumed in coming up.
Sol: Let
fuel consumed in coming up is x.
Thus equation is: x+1.25x=4.5
Ans: 2gallons
64) 40%
employees are male if 60% of supervisors are male so for 100% is 26.4%so the
probability is ……. Ans:
0.264
65)
Gavaskar average in first 50 innings was 50. After the 51st innings his average
was 51 how many runs he made in the 51st innings
Sol: first
50 ings.- run= 50*50=2500
51st ings. - Avg 51. So total
run =51*51=2601.
So run scored in that
ings=2601-2500=101 runs.
Ans: 101 runs
66) Hansie made the following
amounts in seven games of cricket in
Ans: Rs.16 crore
67) Average of 5 numbers is -10
sum of 3 numbers is 16, what is the average of other two
numbers? Ans: -33
68) If A, B
and C are the mechanisms used separately to reduce the wastage of fuel by 30%,
20% and 10%. What will be the fuel economy if they were used combined. Ans: 20%
69) In 80
coins one coin is counterfeit what is minimum number of weighing to find out
counterfeit coin
Sol: the
minimum number of weightings needed is just 5.as shown below
(1) 80->30-30 (2) 15-15 (3) 7-7 (4)
3-3 (5) 1-1
Ans: 5.
70) 2 oranges, 3 bananas and 4 apples cost Rs.15. 3 oranges, 2 bananas, and
1 apple costs Rs 10. What is the cost of 3 oranges, 3 bananas and 3 apples?
Sol:
2x+3y+4z=15
3x+2y+z=10
Adding
5x+5y+5z=25
x+y+z=5 that is for 1 orange, 1 banana and 1 apple
requires 5Rs.
So for 3 orange, 3 bananas and 3 apples require
15Rs.
i.e. 3x+3y+3z=15
Ans:
15
71) In 8*8
chess board what is the total number of squares refers odele discovered
that there are 204 squares on the board .We found that you would add the
different squares
= 1 + 4 + 9 + 16+ 25 + 36 + 49
+ 64. =204
Also in 3*3 tic tac toe board what is the total no of squares
Ans: 14 i.e.
9+4(bigger ones) +1 (biggest one)
If you get 100*100 board just use the formula the formula for the sum of
the first n perfect squares is
n x (n + 1) x (2n + 1)
______________
6
72) One
fast typist type some matter in 2hr and another slow typist type the same
matter in 3hr. If both do combine in how much time they will finish.
Sol: Faster
one can do 1/2 of work in one hour slower one can do 1/3 of work in one hour
both they do (1/2+1/3=5/6) the work in one hour. So work will b finished in
6/5=1.2 hour
i e 1 hour 12 min.
Ans: 1 hour 12 min.
73)If
Rs20/- is available to pay for typing a research report & typist A produces
42 pages and typist B produces 28 pages. How much should typist A receive?
Sol: Find 42
% of 20 rs with respect to 70 (i.e. 28 + 42)
==> (42 * 20)/70 ==> 12 Rs
Ans: 12 Rs
74) In
some game 139 members have participated every time one fellow will get bye what
is the number of matches to choose the champion to be held?
Ans: 138 matches
(Explanation: since one player gets a bye in each round, he
will reach the finals of the tournament without playing a match.
Therefore 137 matches should be
played to determine the second finalist from the remaining 138 players
(excluding the 1st player)
Therefore to determine the
winner 138 matches should be played.)
75) ONE
RECTANGULAR PLATE WITH LENGTH 8INCHES, BREADTH 11 INCHES AND 2 INCHES THICKNESS
IS THERE.WHAT IS THE LENGTH OF THE CIRCULAR ROD WITH DIAMETER 8 INCHES AND
EQUAL TO VOLUME OF RECTANGULAR PLATE?
Sol: Vol. of rect.
plate= 8*11*2=176
Area of rod= (22/7)*(8/2)*(8/2)
= (352/7)
Vol. of rod=area*length=vol. of
plate
So length of rod= vol of
plate/area=176/ (352/7) =3.5
Ans: 3.5
76) One
tank will fill in 6 minutes at the rate of 3cu ft /min, length of tank is 4 ft
and the width is 1/2 of length, what is the depth of the tank?
Ans: 3 ft 7.5 inches
77) A power unit is there by the bank of the river of
750 meters width. A cable is made from power unit to power a plant opposite to
that of the river and 1500mts away from the power unit. The cost of the cable
below water is Rs. 15/- per meter and cost of cable on the bank is Rs.12/- per
meter. Find the total of laying the cable.
Ans: 1000
(24725 - cost) 20250
Ans: Rs. 22,500 (hint: the plant is on the other side of the plant
i.e. it is not on the same side as the river)
78) The
cost of one pencil, two pens and four erasers is Rs.22 while the cost of five
pencils, four pens and two erasers is Rs.32.How much will three pencils, three
pens and three erasers cost?
Sol :( let x
b pencil, y b pen and z b eraser... u get x+2y+4z=22 and 5x+4y+2z=32 add
6x+6y+6z=54 div by 2 you get 27)
Ans: 27
79) A man
has to get air-mail. He starts to go to airport on his motorbike. Plane comes
early and the mail is sent by a horse-cart. The man meets the cart in the
middle after half an hour. He takes the mail and returns back, by doing so, he
saves twenty minutes. How early did the plane arrive?
Sol: Assume he
started at 1:00, so at 1:30 he met cart .He returned home at 2:00.so it took
him 1 hour for the total journey. By doing this he saved 20 min. So the actual
time if the plane is not late is 1 hour and 20 min. So the actual time of plane
is at 1:40.The cart traveled a time of 10 min before it met him. So the
plane is 10 min early.
Ans: 10 min
80) Ram
singh goes to his office in the city every day from his suburban house. His
driver Mangaram drops him at the railway station in the morning and picks him
up in the evening. Every evening Ram singh reaches the station at 5 o'clock.
Mangaram also reaches at the same time. One day Ram singh started early from
his office and came to the station at 4 o'clock. Not wanting to wait for the
car he starts walking home. Mangaram starts at normal time, picks him up on the
way and takes him back house, half an hour early. How much time did Ram singh
walked?
81) 2
trees are there. One grows at 3/5 of the other. In 4 years total growth of the
trees is 8 ft. what growth will smaller tree have in 2 years.
Sol: THE
BIG TREE GROWS 8FT IN 4 YEARS=>THE BIG TREE GROWS 4FT IN 2 YEARS.WHEN
WE DIVIDE 4FT/5=.8*3=>2.4
4 (x+ (3/5) x) =88x/5=2x=5/4
After 2 years x= (3/5)*(5/4)*2 =1.5 (less than 2 feet)
82) There
is a six digit code. Its first two digits, multiplied by 3 gives all ones. And
the next two digits multiplied by 6 give all twos. Remaining two digits
multiplied by 9 gives all threes. Then what is the code?
Sol: Assume
the digit xx xx xx (six digits)
First Two digit
xx * 3=111
xx
=111/3=37
(First two digits of 1 is not divisible by
3 so we can use 111)
Second Two digit xx*6=222
xx=222/6=37
(First two digits of 2 is not divisible by
6 so we can use 222)
Third Two digit xx*9=333
xx=333/9=37
(First two digits of 3 is not divisible by
9 so we can use 333)
83) There
are 4 balls and 4 boxes of colors yellow, pink, red and green. Red ball is in a
box whose color is same as that of the ball in a yellow box. Red box has green
ball. In which box you find the yellow ball?
Sol: Yellow
box can have either of pink/yellow balls.
if we put a yellow ball in
"yellow" box then it would imply that "yellow" is also the
color of the box which has the red ball(because according 2 d question,d box of
the red ball n the ball in the yellow box have same color)
Thus this possibility is ruled
out...
Therefore the ball in yellow
box must be pink, hence the color of box contain in red ball is also pink....
=>the box color left out is
"green", which is allotted to the only box left, the one which has
yellow ball.
Ans: green
84) A bag
contains 20 yellow balls, 10 green balls, 5 white balls, 8 black balls, and 1
red ball. How many minimum balls one should pick out so that to make sure the
he gets at least 2 balls of same color.
Sol:
suppose he picks 5 balls of all different colors then when he picks up the
sixth one, it must match any on of the previously drawn ball color. Thus
he must pick 6 balls
Ans: he should pick 6 balls totally.
85) WHAT
IS THE NUMBER OF ZEROS AT THE END OF THE PRODUCT OF THE NUMBERS FROM 1 TO 100?
Sol: For
every 5 in unit place one zero is added
so between 1 to 100 there are
10 nos like 5,15,25,..,95 which has 5 in unit place.
Similarly for every no
divisible by 10 one zero is added in the answer so between 1 to 100
, 11 zeros are added
For 25, 50,
75 3 extra zeros are added
So total no of zeros are
10+11+3=24
86) There
are two numbers in the ratio 8:9. If the smaller of the two numbers is
increased by 12 and the larger number is reduced by 19 thee the ratio of the
two numbers is 5:9.
Find the larger number?
Sol: 8x: 9x
initially
8x+ 12: 9x - 19 = 5x: 9x
8x+12 = 5x
-> x = 4
9x = 36 (NOT SURE ABOUT THE ANSWER)
87) There
are three different boxes A, B and C. Difference between weights of A and B is
3 kgs. And between B and C is 5 kgs. Then what is the maximum sum of the
differences of all possible combinations when two boxes are taken each time
Sol: A-B = 3
B-c = 5
A-c = 8 So sum of diff = 3+5+8 = 16Kgs